Consider the situation shown in figure.The switch is closed at `t=0`when the capacitor `C_(1)`as a function of time `t`.

The switch shown n the figure is closed at t=0 . The charge on the capacitor as a function of time is given by

The switch shown n the figure is closed at t=0 . The charge on the capacitor as a function of time is given by

In the following circuit, the switch S is closed at t = 0. The charge on the capacitor C_(1) as a function of time will be given by (C_(eq)=(C_(1)C_(2))/(C_(1)+C_(2)))

In the following circuit, the switch S is closed at t = 0. The charge on the capacitor C_(1) as a function of time will be given by (C_(eq)=(C_(1)C_(2))/(C_(1)+C_(2)))

In the circuit shown in fig, if the switch S is closed at t = 0 , the capacitor charges with a time constant

Consider the circuit shown. Switch is closed at t=0. Find the current through the battery as a function of time. Initially capacitor was uncharged.

In the circuit diagram shown, intially there is no energy in the inductor and the capacitor. The switch is closed at t=0 . Find the current I as a function of time t .

Consider the situation shown in figure. If the switch is closed and after some time it is opened again, the closed loop will show

Consider the situation shown in figure. If the switch is closed and after some time it is opened again, the closed loop will show