A carton consists of 100 shirts of which 88 are good and 8 have minor defects. Rohit, a trader, will only accept the shirts which are good, But, Kamal, an another trader, will only reject the shirts which have major defects. One shirt is drawn at random from the carton. What is the probability that is acceptable to (i) Rohit and (ii) Kamal?

Explanation

To solve the problem, we need to find the probability that a randomly drawn shirt from the carton is acceptable to Rohit and Kamal.

### Step-by-Step Solution:

1. **Identify Total Shirts**:
- The total number of shirts in the carton is given as 100.

2. **Identify Good and Defective Shirts**:
- Out of the 100 shirts, 88 are good and 8 have minor defects.
- It is important to note that the problem states that there are no major defects mentioned, so we assume that all shirts with minor defects are still acceptable to Kamal.

3. **Calculate Probability for Rohit**:
- Rohit only accepts good shirts.
- The number of good shirts = 88.
- The probability that a shirt is acceptable to Rohit is calculated as:
\[ P(\text{Rohit}) = \frac{\text{Number of good shirts}}{\text{Total number of shirts}} = \frac{88}{100} = \frac{22}{25} \]

4. **Calculate Probability for Kamal**:
- Kamal rejects shirts with major defects. Since there are no major defects mentioned, he accepts all good shirts and the shirts with minor defects.
- The number of shirts acceptable to Kamal = Number of good shirts + Number of shirts with minor defects = 88 + 8 = 96.
- The probability that a shirt is acceptable to Kamal is calculated as:
\[ P(\text{Kamal}) = \frac{\text{Number of acceptable shirts}}{\text{Total number of shirts}} = \frac{96}{100} = \frac{24}{25} \]

### Final Answers:
- (i) The probability that the shirt is acceptable to Rohit is \( \frac{22}{25} \).
- (ii) The probability that the shirt is acceptable to Kamal is \( \frac{24}{25} \).