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In the given figure, E is a point on si...

In the given figure, E is a point on side CB produced of an isosceles `Delta ABC` with `AB=AC.`. If `AD bot BC and EF bot AC`, prove tha `Delta ABD~ Delta ECF`

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To prove that triangle \( \Delta ABD \sim \Delta ECF \), we will follow these steps: ### Step 1: Identify the Given Information We are given that \( \Delta ABC \) is an isosceles triangle with \( AB = AC \), and \( AD \perp BC \) and \( EF \perp AC \). ### Step 2: Establish Corresponding Angles Since \( AB = AC \) in triangle \( ABC \), by the property of isosceles triangles, the angles opposite to the equal sides are equal. Thus, we have: \[ ...
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