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In the given figure, if `angle ADE= angle B`, show that `Delta ADE~ Delta ABC`. If `AD=3.8 cm, AE=3.6 cm, BE=2.1 cm, and BC =4.2 cm`, find DE.

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The correct Answer is:
`2.8 cm`
`angle ADE= angle B, angleA = angle A`
`Delta ADE~Delta ABC rArr (AD)/(AB)= (DE)/(BC) rArr (3.8)/((3.6+2.1))=(x)/(4.2)`. Find x.
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RS AGGARWAL-TRIANGLES-Exercise 7B
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