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In the given figure, angle 1 = angle 2 a...

In the given figure, `angle 1 = angle 2 and (AC)/(BD)=(CB)/(CE)` prove that `Delta ACB~ Delta DCE`.

Text Solution

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`(AC)/(BD)=(CB)/(CE) rArr (AC)/(CB)=(BD)/(CE)`
Also, `angle 2 = angle 1 rArr BD= DC`.
Thus, `(AC)/(CB)=(DC)/(CE) rArr (AC)/(DC)=(CB)/(CE)`
and `angle ACB= angle DCE = angle C`
`:. Delta ACB~ Delta DCE` [ SAS- similarity]
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