In the given figure, O is point inside a `Delta PQR` such that `angle POR=90^(@), OP=6 cm and OR=8 cm`. If `PQ=24cm and QR=26cm`, prove that `Delta PQR` is right angled.

Explanation

`PR=sqrt(OP^(2)+OR^(2))=sqrt(6^(2)+8^(2))=10`
Now, `24^(2)+10^(2)=26^(2), i.e., PQ^(2)+PR^(2)=QR^(2)rArr angle QPR=90^(@)`