ABC is an isosceles triangle, right-angled at B. Similar trianles ACD and ABE are constructed on sides AC and AB. Find ratio between the areas of `Delta ABE and Delta ACD`.

Answer

`1:2`

Explanation

`(ar (Delta ABC))/(ar (Delta ACD))=(AB^(2))/(AC^(2))=(AB^(2))/(2AB^(2))=(1)/(2) [ :. AC^(2)=AB^(2)+BC^(2)=2AB^(2)]`