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Delta ABC~Delta DEF and their perimeters...

`Delta ABC~Delta DEF` and their perimeters are 32 cm and 24 cm respectively. If AB=10 cm then DE=?

A

`8` cm

B

`7.5` cm

C

`15` cm

D

`5sqrt(3)` cm

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The correct Answer is:
To solve the problem, we will use the concept of similar triangles and the relationship between their corresponding sides and perimeters. ### Step-by-Step Solution: 1. **Identify the given information:** - The perimeters of triangles ABC and DEF are given as: - Perimeter of ΔABC = 32 cm - Perimeter of ΔDEF = 24 cm - The length of side AB is given as: - AB = 10 cm 2. **Set up the ratio of the perimeters:** Since the triangles are similar (ΔABC ~ ΔDEF), the ratio of their corresponding sides is equal to the ratio of their perimeters. Therefore, we can set up the following ratio: \[ \frac{\text{Perimeter of } \Delta ABC}{\text{Perimeter of } \Delta DEF} = \frac{AB}{DE} \] Substituting the known values: \[ \frac{32}{24} = \frac{10}{DE} \] 3. **Simplify the ratio of the perimeters:** We can simplify \(\frac{32}{24}\): \[ \frac{32}{24} = \frac{4}{3} \] So we have: \[ \frac{4}{3} = \frac{10}{DE} \] 4. **Cross-multiply to find DE:** Cross-multiplying gives us: \[ 4 \cdot DE = 3 \cdot 10 \] Simplifying this: \[ 4 \cdot DE = 30 \] 5. **Solve for DE:** Now, divide both sides by 4 to isolate DE: \[ DE = \frac{30}{4} = 7.5 \text{ cm} \] ### Final Answer: \[ DE = 7.5 \text{ cm} \]
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