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A(7, -3), B(5, 3) and C(3, -1) are the v...

A(7, -3), B(5, 3) and C(3, -1) are the vertices of a `Delta ABC` and AD is its median. Prove that the median AD divides `Delta ABC` into two triangles of equal areas.

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If A (4, 2), B (7, 6) and C (1, 4) are the vertices of a DeltaABC and AD is its median, prove that the median AD divides DeltaABC into two triangles of equal areas.

If A(4,-6),B(3,-2)and C(5,2) are the vertices of a DeltaABC and AD is its median, prove that the median AD divides DeltaABC into two triangles of equal areas.

Knowledge Check

  • If A(4, 2), B(6, 5) and C(1, 4) be the vertices of Delta ABC and AD is a median, then the coordinates of D are

    A
    `((5)/(2), 3)`
    B
    `(5, (7)/(2))`
    C
    `((7)/(2), (9)/(2))`
    D
    none of these
  • If A (1,-2), B (-2,3) and C(2,-5) are the vertices of Delta ABC, then the equation of the median BE is

    A
    7x+13y+47=0
    B
    13x+7y+5=0
    C
    7x-13y+5=0
    D
    none of these
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