If the sixth term of an AP is zero then show that its 33rd term is three times its 15th term.

Explanation

To solve the problem, we need to show that if the sixth term of an arithmetic progression (AP) is zero, then the 33rd term is three times the 15th term. Let's denote the first term of the AP as \( A \) and the common difference as \( D \).

### Step-by-Step Solution:

1. **Identify the sixth term of the AP**:
The formula for the \( n \)-th term of an AP is given by:
\[
T_n = A + (n - 1)D
...