The 17th term of an AP exceeds its 10th ...

The 17th term of an AP exceeds its 10th term by 21. The common difference of the AP is

A

3

B

2

C

`-3`

D

`-2`

Verified by Experts

The correct Answer is:

A

`(T_(17) - T_(10)) = 21 rArr (a+16d) - (a+9d) = 21 rArr 7d = 21 rArr d = 3.`

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