In a single throw of two dice, find the probability of obtaining 'a total of 8'.

Explanation

We know that in a single throw of two dice, the total number of possible outcomes is `(6 xx 6) = 36`.
Let S be the sample space. Then, n(S) = 36.
Let E = event of getting a total of 8. Then,
`E = {(2, 6), (3, 5), (4, 4), (5, 3), (6, 2)}` and, therefore, n(E) = 5.
`therefore` P(getting a total of 8) `= P(E) = (n(E))/(n(S)) = 5/36.`