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An urn contains 9 red, 7 white and 4 bla...

An urn contains 9 red, 7 white and 4 black balls. A ball is drawn at random. Find the probability that the ball drawn is
(i) red (ii) white (iii) red or white
(iv) white or black (v) not white

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The correct Answer is:
To solve the problem, we will calculate the probability for each part step by step. ### Given: - Red balls = 9 - White balls = 7 - Black balls = 4 ### Total number of balls: Total = Red + White + Black = 9 + 7 + 4 = 20 ### (i) Probability of drawing a red ball: The probability of an event is given by the formula: \[ P(A) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \] For a red ball: - Number of favorable outcomes = 9 (red balls) - Total outcomes = 20 So, \[ P(\text{Red}) = \frac{9}{20} \] ### (ii) Probability of drawing a white ball: For a white ball: - Number of favorable outcomes = 7 (white balls) - Total outcomes = 20 So, \[ P(\text{White}) = \frac{7}{20} \] ### (iii) Probability of drawing a red or white ball: The probability of drawing a red or white ball can be calculated by adding the probabilities of drawing a red ball and a white ball: \[ P(\text{Red or White}) = P(\text{Red}) + P(\text{White}) \] So, \[ P(\text{Red or White}) = \frac{9}{20} + \frac{7}{20} = \frac{16}{20} = \frac{4}{5} \] ### (iv) Probability of drawing a white or black ball: Similarly, we can calculate the probability of drawing a white or black ball: \[ P(\text{White or Black}) = P(\text{White}) + P(\text{Black}) \] For a black ball: - Number of favorable outcomes = 4 (black balls) - Total outcomes = 20 So, \[ P(\text{Black}) = \frac{4}{20} = \frac{1}{5} \] Now, adding the probabilities: \[ P(\text{White or Black}) = \frac{7}{20} + \frac{4}{20} = \frac{11}{20} \] ### (v) Probability of not drawing a white ball: The probability of not drawing a white ball can be found by subtracting the probability of drawing a white ball from 1: \[ P(\text{Not White}) = 1 - P(\text{White}) \] So, \[ P(\text{Not White}) = 1 - \frac{7}{20} = \frac{20 - 7}{20} = \frac{13}{20} \] ### Summary of Results: 1. Probability of red ball = \( \frac{9}{20} \) 2. Probability of white ball = \( \frac{7}{20} \) 3. Probability of red or white ball = \( \frac{4}{5} \) 4. Probability of white or black ball = \( \frac{11}{20} \) 5. Probability of not white ball = \( \frac{13}{20} \)
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RS AGGARWAL-PROBABILITY-Exercise 31 A
  1. In a single throw of two dice, find (i) P (an odd number on the firs...

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  2. A bag contains 4 white and 5 black balls. A ball is drawn at random fr...

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  3. An urn contains 9 red, 7 white and 4 black balls. A ball is drawn at r...

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  4. In a lottery, there are 10 prizes and 25 blanks. Find the probability ...

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  5. If there are 2 children in a family, find the probability that there i...

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  6. Three unbiased coins are tossed once. Find the probability of getting ...

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  7. In a single throw of two dice, detemine the probability of not getting...

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  8. If a letter is chosen at random from the English alphabet, find the pr...

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  9. A card is drawn at random from a well - shuffled pack of 52 cards. Wha...

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  10. Tickets numbered from 1 to 12 are mixed up together and then a ticket ...

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  11. What is the probability that on ordinary year has 53 Tuesdays ?

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  12. What is the probability that a leap year has 53 Sundays ?

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  13. What is the probability that in a group of two people, both will have ...

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  14. Which of the following cannot be the probability of occurrence of an e...

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  15. If 7/10 is the probability of occurrence of an event, what is the prob...

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  16. The odds in favour of the occurrence of an event are 8 : 13. Find the ...

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  17. If the odds against the occurrence of an event be 4 : 7, find the prob...

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  18. If 5/14 is the probability of occurrence of an event, find (i) the o...

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  19. Two dice are thrown. Find (i) the odds in favour of getting the sum ...

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  20. A combination lock on a suitcase has 3 wheels, each labelled with nine...

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