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What is the probability that on ordinary year has 53 Tuesdays ?

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To determine the probability that an ordinary year has 53 Tuesdays, we first need to understand how many days are in an ordinary year and how the days of the week are distributed. ### Step 1: Understand the number of days in an ordinary year An ordinary year has 365 days. **Hint:** Remember that a week has 7 days. ### Step 2: Calculate the number of weeks in an ordinary year To find out how many complete weeks are in 365 days, we divide 365 by 7. \[ \text{Number of weeks} = \frac{365}{7} = 52 \text{ weeks} \text{ and } 1 \text{ day} \] **Hint:** When you divide, note the quotient and the remainder. ### Step 3: Determine the distribution of days Since there are 52 complete weeks, each day of the week (Monday, Tuesday, ..., Sunday) will occur 52 times. The extra day (the remainder from the division) will determine if there is an additional occurrence of a specific day. **Hint:** Think about how the extra day affects the count of each day of the week. ### Step 4: Identify the extra day The extra day can be any one of the 7 days of the week. Therefore, the extra day could be: - Sunday - Monday - Tuesday - Wednesday - Thursday - Friday - Saturday **Hint:** List out the days of the week to visualize this. ### Step 5: Count the occurrences of Tuesdays If the extra day is a Tuesday, then there will be 53 Tuesdays in that year. If the extra day is any other day, there will only be 52 Tuesdays. **Hint:** Consider how many scenarios lead to having 53 Tuesdays. ### Step 6: Calculate the probability Since there are 7 possible days for the extra day, and only 1 of those days (Tuesday) results in having 53 Tuesdays, the probability can be calculated as follows: \[ \text{Probability of 53 Tuesdays} = \frac{\text{Number of favorable outcomes}}{\text{Total possible outcomes}} = \frac{1}{7} \] **Hint:** Remember the formula for probability: P(Event) = (Number of favorable outcomes) / (Total possible outcomes). ### Final Answer The probability that an ordinary year has 53 Tuesdays is \(\frac{1}{7}\). ---

To determine the probability that an ordinary year has 53 Tuesdays, we first need to understand how many days are in an ordinary year and how the days of the week are distributed. ### Step 1: Understand the number of days in an ordinary year An ordinary year has 365 days. **Hint:** Remember that a week has 7 days. ### Step 2: Calculate the number of weeks in an ordinary year ...
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RS AGGARWAL-PROBABILITY-Exercise 31 A
  1. An urn contains 9 red, 7 white and 4 black balls. A ball is drawn at r...

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  2. In a lottery, there are 10 prizes and 25 blanks. Find the probability ...

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  3. If there are 2 children in a family, find the probability that there i...

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  4. Three unbiased coins are tossed once. Find the probability of getting ...

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  5. In a single throw of two dice, detemine the probability of not getting...

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  6. If a letter is chosen at random from the English alphabet, find the pr...

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  7. A card is drawn at random from a well - shuffled pack of 52 cards. Wha...

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  8. Tickets numbered from 1 to 12 are mixed up together and then a ticket ...

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  9. What is the probability that on ordinary year has 53 Tuesdays ?

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  10. What is the probability that a leap year has 53 Sundays ?

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  11. What is the probability that in a group of two people, both will have ...

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  12. Which of the following cannot be the probability of occurrence of an e...

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  13. If 7/10 is the probability of occurrence of an event, what is the prob...

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  14. The odds in favour of the occurrence of an event are 8 : 13. Find the ...

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  15. If the odds against the occurrence of an event be 4 : 7, find the prob...

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  16. If 5/14 is the probability of occurrence of an event, find (i) the o...

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  17. Two dice are thrown. Find (i) the odds in favour of getting the sum ...

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  18. A combination lock on a suitcase has 3 wheels, each labelled with nine...

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  19. In a lottery, a person choses six different natural numbers at rand...

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  20. In a single throw of three dice, determine the probability of getti...

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