A group of electric lamps having total power rating of 900 watt is supplied an a.c. voltage `E = 200 cos (314 t + 60^(@))`. Find rms value of alternating current.

A group of electric lamps having total power rating of 1000 watt is supplied an a.c. voltage. E = 200 cos (314t + 60^@) Find r.m.s. value of a.c. current.

A group of electric lamps having a total power rating of 1000 watt is supplied by an AC voltage E=200sin(310t+60^(@)) . Then the r.m.s value of the circuit current is

A group of electric lamps having a total power rating of 1000 watt is supplied by an AC voltage E=200sin(310t+60^(@)) . Then the r.m.s value of the circuit current is

A group of electric lamps having total power rating of 600 W, 200 V is supplied by an AC voltage V=169sin(314t+60^(@)) . The rms vlaue of the current is

[" 8.A group of electric lamp having a total power rating "1000W" is supplied by an "AC],[" voltage "E=200sin(310t+60^(@))" .The rms value of current in the circuit is "]

A group of electric bulbs have a power rating of 300 watt. An a.c. voltage V - 314 sin (314 t + pi//3) is applied to the group. Calculate the effective current.

The equation of an a.c. voltage is V = 200 sin 50 pi t Then, the r.m.s. value of voltage is

The instantaneous current from an a.c. source is I = 6 sin 314 t. What is the r.m.s. value of the current?