If the plane `x/2+y/3+z/4=1` cuts the coordinate axes in `A, B,C,` then the area of triangle `ABC` is

If the plane 3x+4y-3z+2=0 cuts the coordinate axes at A, B, C, then the centroid of the triangle ABC is

The plane x / 2 + y / 3 + z / 4 = 1 cuts the co-ordinate axes in A, B, C : then the area of the DeltaABC is

The plane x/4 + y/3 -z/5 =1 cuts the axes at A, B, C then the area of the triangle ABC is

The plane (x)/(2)+(y)/(3)+(z)/(4)=1 cuts the co- ordinate axes in A,B,C: then the area of the Delta ABC is

If the plane 56x+4y+9z=2016 meets the coordinate axes in A,B,C then the centroid of the triangle ABC is

The plane x/2+y/3+z/4 = 1 cuts the axes A, B, C then the area of the triangle ABC is