Rate constant for the decomposition of ethylene oxide into `CH_(4)` and CO may be described be the equation. `logk(s)^(-1)=14.34-(1.25xx10^(4))/(T)`
(a) What is the energy of activation of this reaction ?
(b) What is the value of k at 670K ?

The rate constant for the first order decomposition of ethylene oxide into CH_(4) and CO, may be describe by log k("in" s^(-1))=14.34-(1.25xx10^(4)K)/T The activation energy of the reaction is

The rate constant for the first order decomposition of a certain reaction is described by the equation log k (s^(-1)) = 14.34 - (1.25 xx 10^(4)K)/(T) (a) What is the energy of activation for the reaction? (b) At what temperature will its half-life period be 256 min ?

The rate constant for the first order decompoistion of a certain reaction is described by the equation log k (s^(-1)) = 14.34 - (1.25 xx 10^(4)K)/(T) (a) What is the energy of activation for the reaction? (b) At what temperature will its half-life periof be 256 min ?

The rate constant for the decompoistion of a certain reaction is described by the equation: log k(s^(-1)) = 14 - (1.25 xx 10^(4) K)/(T) Energy of activation (in kcal ) is

The rate constant for the decompoistion of a certain reaction is described by the equation: log k(s^(-1)) = 14 - (1.25 xx 10^(4) K)/(T) Energy of activation (in kcal ) is

The rate constant for the decompoistion of a certain reaction is described by the equation: log k(s^(-1)) = 14 - (1.25 xx 10^(4) K)/(T) What is the effect on the rate of reaction at 127^(@)C , if in the presence of catalyst, energy of activation is lowered by 10 kJ mol^(-1) ?