If force `vecf=(3xveci+y^(2))` W is acting on a body and body moves from (1m, 2m, 1m) to (2m, 3, 8m), then find the work done due to the force

If force vecf=(3xveci+y^(2)vecj) N is acting on a body and body moves from (1m, 2m, 1m) to (2m, 3, 8m), then find the work done due to the force

A force vecF=xhati+y^(2)hatjN acts on a particle and the particle moves from (1,2) m to (–3,4) m . Find work done by the force vecF .

A force of 20 N acts on a body and the body moves through 1 m at an angle of 45^(@) in the direction of the force. The work done by the force is

The work done by a force on a body moving from (1,4) m to (3,8) m is 44 J. The force can be :

Consider a variable force F=(3x+5)N acting on a body and if it is displaced from x=2m to x=4m , calculate the work done by this force.

Consider a variable force F=(3x+5)N acting on a body and if it is displaced from x=2m to x=4m , calculate the work done by this force.

A force of 35N acts in the direction parallel to 2 hat(i) + 3hat(j) + 6hat(k) and it displaces a body from (1m, 0m, 3m) to (3m, 4m, 1m) find the work done

A force vecF=(3x^(2)+2x-7)N acts on a 2 kg body as a result of which the body gets displaced from x=0 to x=5m. The work done by the force will be –