If P.E. of a system is given by relation `U= (A)/(x^(2))-(B)/(x)`, where 'A'and'B' are positive constant, then the mean positive of S.H.M.is

In a molecule, the potential energy between two atoms is given by U (x) = (1)/(x^(12)) -(b)/(x^(6)) . Where 'a' and 'b' are positive constants and 'x' is the distance between atoms. Find the value of 'x' at which force is zero and minimim P.E at that point.

In a molecule, the potential energy between two atoms is given by U(x)=(a)/(x^(12))-(b)/(x^(6)) . Where a and b are positive constants and x is the distance between atoms. Find the value of x at which force is zero and minimum P.E. at that point.

A particle located in one dimensional potential field has potential energy function U(x)=(a)/(x^(2))-(b)/(x^(3)) , where a and b are positive constants. The position of equilibrium corresponds to x equal to

A particle located in one dimensional potential field has potential energy function U(x)=(a)/(x^(2))-(b)/(x^(3)) , where a and b are positive constants. The position of equilibrium corresponds to x equal to

A particle located in one dimensional potential field has potential energy function U(x)=(a)/(x^(2))-(b)/(x^(3)) , where a and b are positive constants. The position of equilibrium corresponds to x equal to

The potential energy between two atoms in a molecule is given by U(x)= (1)/(x^(12))-(b)^(x^(6)) , where a and b are positive constants and x is the distance between the atoms. The atom is in stable equilibirum when

The potential energy between two atoms in a molecule is given by U(x)= (a)/(x^(12))-(b)/(x^(6)) , where a and b are positive constants and x is the distance between the atoms. The atom is in stable equilibrium when