Home
Class 12
CHEMISTRY
[" 45.For the following equilibrium "N(2...

[" 45.For the following equilibrium "N_(2)O_(4)rightleftharpoons2NO_(2)" ; "],[K_(c)=0.67" .If we start with "3" moles of "NO_(2)" and "1mol theta],[" of "N_(2)O_(4)" in "1L" flask,then "NO_(2)" present at equilibrium "],[" is "],[[" (a) "1.5mol," (b) "2.0mol],[" (c) "0.5mol," (d) "1.0mol]]

Promotional Banner

Similar Questions

Explore conceptually related problems

For the following equilibrium in gaseous phase, N_(2)O_(4)hArr 2NO_(2) NO_(2) is 50% of the total volume, when equilibrium is set up. Hence, percent dissociation of N_(2)O_(4) is :

Initially 0.4 mole of N_(2) and 0.9 mole of O_(2) were mixed then moles of N_(2),O_(2) and NO at equilibrium are (approximate):

" Q.2"[" At "30^(@)C" ,the gaseous mixture for the equilibrium,"N_(2)(g)+O_(2)(g)rightleftharpoons2NO(g)" contains "56gm" of "N_(2)" ,"128gm" of "O_(2)" and "],[120gm" of "NO" at equilibrium weights at one atmosphere pressure.The value of "K_(P)" at "30^(@)C" is "]

If alpha is the degree of dissociation of N_(2)O_(4) in the reaction : N_(2)O_(4)hArr 2NO_(2) then at equilibrium, the total number of moles of N_(2)O_(4) and NO_(2) present is :

Vapour density of the equilibrium mixture of NO_(2) and N_(2)O_(4) is found to be 40 for the equilibrium N_(2)O_(4) hArr 2NO_(2) Calculate

Vapour density of the equilibrium mixture of NO_(2) and N_(2)O_(4) is found to be 40 for the equilibrium N_(2)O_(4) hArr 2NO_(2) Calculate