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evaluate: |(0,xy^(2),xz^(2)),(x^(2)y,0,y...

evaluate: `|(0,xy^(2),xz^(2)),(x^(2)y,0,yz^(2)),(x^(2)z,zy^(2),0)|`

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Using the properties of determinants in Exercise 1 to 6, evaluate |{:(0,xy^2,xz^2),(x^2y,0,yz^2),(x^2z,y^2z,0):}|

if x=31,y=32 and z=33 then the value of |{:((x^(2)+1)^(2),,(xy+1)^(2),,(xz+1)^(2)),((xy+1)^(2),,(y^(2)+1)^(2),,(yz+1)^(2)),((xz+1)^(2),,(yz+1)^(2),,(z^(2)+1)^(2)):}|" is " "____"

if x=31,y=32 and z=33 then the value of |{:((x^(2)+1)^(2),,(xy+1)^(2),,(xz+1)^(2)),((xy+1)^(2),,(y^(2)+1)^(2),,(yz+1)^(2)),((xz+1)^(2),,(yz+1)^(2),,(z^(2)+1)^(2)):}|" is " "____"

if x=31,y=32 and z=33 then the value of |{:((x^(2)+1)^(2),,(xy+1)^(2),,(xz+1)^(2)),((xy+1)^(2),,(y^(2)+1)^(2),,(yz+1)^(2)),((xz+1)^(2),,(yz+1)^(2),,(z^(2)+1)^(2)):}|" is " "____"

prove that: |(y^(2)z^(2),yz,y+z),(z^(2)x^(2),zx,z+x),(x^(2)y^(2),xy,x+y)|=0

prove that: |(y^(2)z^(2),yz,y+z),(z^(2)x^(2),zx,z+x),(x^(2)y^(2),xy,x+y)|=0

Using properties of determinants,prove that [[-yz,y^(2)+yz,z^(2)+yzx^(2)+xz,-xz,z^(2)+xyx^(2)+xy,y^(2)+xy,-xy]]=(xy+yz+zx)^(2)

xy,xz,x^(2)+1y^(2)+!,yz,xyyz,z^(2)+1,xz]|=1+x^(2)+y^(2)+z^(2)

Evaluate : (2x-y+3z)(4x^(2)+y^(2)+9z^(2)+2xy+3yz-6xz)