In the given figure, ABCD is a square, M is the midpoint of AB and `PQ_|_CM` meets AD at P and CB produced at Q. Prove that (i) PA = QB and (ii) `CP=AB+PA.`

ABCD is a square M is the mid point of AB . PQbotCM . PQ meets AD at P and CB at Q prove that CP=CQ

In the fig. ABCD is a square M is the mid point and PQ bot CM meets AD at and CB produced prove that PA=BQ?

In the given figure, ABCD is a square. M is the mid-point of AB and PQ is perpendicular to CM. CB produced meets PQ at point Q. Prove that : (i) PA = BQ (ii) CP = AB + PA

In the given figure, ABCD is a parallelogram and E is the midpoint of side BC. If DE and AB when produced meet at F, prove that AF = 2AB.

In the given figure,ABCD is a quadrilateral in which AB|DC and P is the midpoint of BC. On producing,AP and DC meet at Q. Prove that (i) AB=CQ, (ii) DQ=DC+AB

In the given figure ABCD is a quadrilateral in which AB"||"DC and P is the midpoint of BC. On producing, AP and DC meet at Q. Prove that (i) AB = CQ, (ii) DQ = DC + AB.

ABCD is a square. P, Q and Rare the points on AB, BC and CD respectively, such that AP = BQ = CR. Prove that: PQ = QR

In trapezium ABCD, AB ||DC and L is the mid-point of BC. Through AL, a line PQ||AD has been drawn which meets AB at P and DC produced to Q. Prove that : ar(ABCD) = ar(APQD)