The area of `triangleABC,=24sqrt(3)`, side a=6, annd side b=16. the value of `angleC` is

The area off triangleABC=12sqrt(3) , side a=6, and side b=9 side c=

The area of triangle whose sides are 10,10 and 16 is

If in triangleABC, a=2sqrt(3), b=3sqrt(2) and angleB = 60^(@) , then find the measure of angleC .

If in triangleABC, a=2sqrt(3), b=3sqrt(2) and angleB = 60^(@) , then find the measure of angleC .

In triangleABC, if a=2, b=1, c=sqrt(3) , then angleC=

In triangleABC , If a=sqrt(3)+1, b=sqrt(3)+1, angleC=60^(@) , then the triangle is

If, in triangleABC, a= sqrt(2), b= sqrt(3), c = sqrt(5) , then the area of triangleABC is

If in a triangle ABC, a=1+sqrt(3)cm,b=2 cm and angleC=60^(@) , then find the other two angles and the thire side

To find the area of triangleABC , note that the lengths of the sides of triangleABC form (3-4-5) Pythagorean triple, where AC=4 . Hence, Find the area of triangleABC .

In triangleABC , if a=sqrt(3)+1, b=sqrt(3)-1 and angleC=60^(@) , then angleA =