A spherical drop of water carrying a charge of `3 xx 10^(-10) C` has potential of 500V at its surface. When two such drops having same charge and radius combine to from a single spherical drop, what is the potential at the surface of the new drop?

A spherical drop of water carries a charge of 10xx10^(-12) C and his a potential of 100V at its surface. Radius of the drop will be

A spherical drop of water carries a charge of 10xx10^(-12)C and has a potential of 100V at its surface. What is the radius of the drop ?

A spherical drop of water carries a charge of 10xx10^(-12) C and has a potential of 100 V at its surface. If eight such charged drops combine to form a single drop, what will be the potential at the surface of the new drop?

A spherical drop of liquid carrying charge, Q has potential V_0 at its surface. If two drops of same charge and radius combine to form of single spherical drop, then the potential at the surface of new drop is (Assume, V = 0 at infinity.)

A spherical drop of water carries a charge of 10xx10^(-12) C and his a potential of 100V at its surface. If eight such charged drops as mentioned above, combine to form a single drop, the potential at the surface of the new drop will be

A mercury drop has potential 'V' on its surface. 1000 such drops combine to form a new drop. Find the potential on the surface of the new drop.

A spherical drop of water bas 3 xx 10^(10) C amount of charge residing on it. 500 V electric potential exists on its surface. Calculate the radius of this drop. If eight such drops (having identical charge and radii) combine to form a single drop, calculate the electric potential on the surface of the new drop. (k = 9 xx 10^(9) SI)

A mercury drop of water has potential 'V' on its surface. 1000 such drops combine to form a new drop. Find the potential on the surface of the new drop.