In a `Delta ABC` line DE is parallel to BC. Prove that `(AD)/(AB) = (DE)/(BC) = (AD)/ (AC)`

If a line intersects sides AB and AC of a Delta ABC at D and E respectively and is parallel to BC, prove that (AD)/(AB)=(AE)/(AC)

In Delta ABC , DE is parallel to BC, If (AD)/(DE) = 3/5 and AC = 4.8 cm , then find AE.

In Delta ABC , DE || BC and CD || EF . Prove that AD^(2) = AF xx AB

In the given figure, ABC is a triangle. DE is parallel to BC and (AD)/(DB) = 3/2 Determine the ratios and (AD)/(AB)

In Delta ABC , AD is a median and AM _|_ BC.Prove that (a) AC^(2) = AD^(2) +BC.DM+ ((BC)/(2))^(2) (b) AB^(2) = AD^(2) -BC.DM+ ((BC)/(2))^(2) (c ) AC^(2) + AB^(2) = 2AD^(2) +(1)/(2) BC^(2)

Given : AB // DE and BC // EF. Prove that: (AD)/(DG) = (CF)/(FG)

In Delta ABC , BD : CD = 3 : 1 and AD _|_ BC . Prove that 2(AB^(2) - AC^(2)) = BC^(2) .

Delta ABC=Delta DEF, Prove that (AB)/(DE)=(AB+BC+AC)/(DE+EF+DF)

In the given figure if DE||BC then prove that (AB)/(DB)=(AC)/(EC)and(AD)/(AB)=(AE)/(AC)

In Delta ABC, AB = BC , AD bot BC and CE bot AB , prove that AD = CE.