Home
Class 12
PHYSICS
A string of negligible mass going over a...

A string of negligible mass going over a clamped pulley of mass m supports a block of mass M as shown in the figure. The force on the pulley by the clamp is given by

A

`gsqrt((M + m)^(2) + M^(2))`

B

`sqrt(2).mg`

C

`sqrt((M +m)^(2) +m^(2)g)`

D

`sqrt(2) Mg`

Text Solution

Verified by Experts

The correct Answer is:
A

Force exerted on the pulley (P) by the clamp ( C)

`F_(PC^(2)) = T^(2) + (M+m)^(2) g^(2)`
`=g^(2)(M^(2) + (M +m)^(2))`
`F_(PC) =gsqrt(M^(2) + (M + m)^(2))`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • LAWS OF MOTION

    MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS (CATEROGY 1: SINGLE OPTION CORRECT TYPE (1 MARK))|10 Videos
  • LAWS OF MOTION

    MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS (CATEGORY 2: SINGLE OPTION CORRECT TYPE (2 MARKS))|1 Videos
  • LAWS OF MOTION

    MTG-WBJEE|Exercise WB JEE WORKOUT (CATEGORY 2: SINGLE OPTION CORRECT TYPE (2 MARKS))|15 Videos
  • KINETIC THEORY OF GASES

    MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS (MCQ)|7 Videos
  • MAGNETIC EFFECT OF CURRENT

    MTG-WBJEE|Exercise WB JEE Previous Years Questions|22 Videos

Similar Questions

Explore conceptually related problems

A mass string going over a clamped pulley of mass m supports a block of mass M as shown in the figure. The force on the pulley by the clamp is given

A block of mass m hangs by means of a string which goes over a pulley of mass m and moment of inertia l, as shown in the diagram. The string does not realtive to the pulley. Find the frequency of small oscillations.

Knowledge Check

  • A string of negligible mass going over a clamped puley of mass m supports a block of mass Mas shown in the figure. The force on the pulley by the clamp is given

    A
    `sqrt2` Mg
    B
    `sqrt2` mg
    C
    `sqrt((M+m)^(2)+m^(2)g)`
    D
    `sqrt((M+m)^(2)+M^(2)g)`
  • A spring of negligible mass going over a clamped pulley of mass m supports a block of mass M as shown in the figure. The force on the pulley by the clamp at the time of equilibrium is given by

    A
    `sqrt(2) Mg`
    B
    `sqrt((mg)^(2)+(kx)^(2))`
    C
    `(sqrt((M+m)^(2)+m^(2)))g`
    D
    `(sqrt((M+m)^(2)+M^(2)))g`
  • Two blocks of masses M_(1)=4 kg and M_(2)=6kg are connected by a string of negligible mass passing over a frictionless pulley as shown in the figure below. The coefficient of friction between the block M_(1) and the horizontal surface is 0.4. when the system is released, the masses M_(1) and M_(2) start accelrating. What additional mass m should be placed over M_(1) so that the masses (M_(1)+m) slide with a uniform speed?

    A
    12 kg
    B
    11 kg
    C
    10 kg
    D
    kg
  • Similar Questions

    Explore conceptually related problems

    Two blocks of masses 2m and m are connected by a light string going over a pulley of mass 2m and radius R as shown in the figure. The system is released from rest. Find the angular momentum of system when the mass 2m has descended through a height h . Assume no slipping.

    A constant force F=m_2g/s is applied on the block of mass m_1 as shown in figure. The string and the pulley are light and the surface of the table is smooth. Find the acceleration of m_1

    Two blocks of masses m_(1) and m_(2) are connected by a string of negligible mass which pass over a frictionless pulley fixed on the top of an inclined plane as shown in figure. The coefficient of friction between m_(1) and plane is mu .

    A string of negligible mass is wrapped on a cylindrical pulley of mass M and radius R. The other end of string is tied to a bucket of mass m. If the pulley rotates about a horizontal axis then the tension in the string is :

    Both the blocks shown in figure have same mass 'm' . All the pulley and strings are massiess.