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A spherical ball A of mass 4 kg, moving ...

A spherical ball A of mass 4 kg, moving along a straight line strikes another spherical ball B of mass 1 kg at rest. After the collision, A and B move with velocities `v_1 m s^(-1) and v_2 m s^(-1)` respectively making angles of `30^@ and 60^@` with respect to the original direction of motion of A. The ratio `v_1/v_2` will be

A

`sqrt(3)/4`

B

`4/sqrt(3)`

C

`1/sqrt(3)`

D

`sqrt(3)`

Text Solution

Verified by Experts

The correct Answer is:
A

Applying the law of conservation of linear momentum along a direction perpendicular to the direction of motion (i.e. along y-axis), we get
`0 +0 = 4v_(1) sin30^(@) -v_(2) sin60^(@)`
`4v_(1) sin30^(@) = v_(2) sin60^(@)`
`v_(1)/v_(2) = (sin 60^(@))/(4 sin 30^(@)) = sqrt(3)/4`
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