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Two wires of equal length and cross-sect...

Two wires of equal length and cross-section area suspended as shown in figure. Their Young's modulus are `Y_(1)` and `Y_(2)` respectively. The equavalent Young's modulus will be

A

`Y_1 + Y_2`

B

`(Y_1 + Y_2)/(2)`

C

`(Y_1 Y_2)/(Y_1 + Y_2)`

D

`sqrt(Y_1 Y_2)`

Text Solution

Verified by Experts

The correct Answer is:
B

` Y = F/A xx (l)/(Delta l)`
Spring constant of wire
`k = (F)/(Delta l) = (YA)/(l)`
`k_(eq) = k_1 + k_2`
or `(Y(2A))/(l) = (Y_1A)/(l) + (Y_2A)/(l) " or " Y = (Y_1 + Y_2)/(2)`
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