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A stress of 1kg//mm^(2) is applied on a ...

A stress of `1kg//mm^(2)` is applied on a wire. If the modulus of elasticity of the wire is `10^(10) "dyne"//cm^(2)`, then the percentage increase in the length of the wire will be

A

9.8E-5

B

0.0098

C

0.098

D

0.98

Text Solution

Verified by Experts

The correct Answer is:
B
`(Delta l)/(l) = ("stress")/(Y) = ( (10^(-1) )^2)/(10^10 "dyne/cm"^2) = 0.0098`
percentage inrease in the length of wire
` = (Delta l)/(l) xx 100 = 0.0098 xx 100 = 0.98%`
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