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An iron bar of length L, cross-section a...

An iron bar of length L, cross-section area A and Young's modulus Y is pulled by a force F from both ends so as to produce an elongation l . Which of the following statements is correct?

A

`l prop Y`

B

`l prop 1/A`

C

`l prop A`

D

`lprop 1/L`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the relationship between the force applied to the iron bar, its elongation, cross-sectional area, and Young's modulus. ### Step-by-Step Solution: 1. **Understanding Young's Modulus**: Young's modulus (Y) is defined as the ratio of longitudinal stress to longitudinal strain. Mathematically, it can be expressed as: \[ Y = \frac{\text{Stress}}{\text{Strain}} \] where: - Stress = \(\frac{F}{A}\) (Force per unit area) - Strain = \(\frac{\Delta L}{L}\) (Change in length per original length) 2. **Expressing Stress and Strain**: - Stress can be calculated as: \[ \text{Stress} = \frac{F}{A} \] - Strain can be expressed as: \[ \text{Strain} = \frac{l}{L} \] where \(l\) is the elongation and \(L\) is the original length of the bar. 3. **Substituting Stress and Strain into Young's Modulus**: Substituting the expressions for stress and strain into the formula for Young's modulus, we get: \[ Y = \frac{\frac{F}{A}}{\frac{l}{L}} = \frac{F \cdot L}{A \cdot l} \] 4. **Rearranging the Equation**: Rearranging the equation gives us: \[ F = \frac{Y \cdot A \cdot l}{L} \] This shows that the force \(F\) is directly proportional to the elongation \(l\) and Young's modulus \(Y\), and inversely proportional to the length \(L\) and the cross-sectional area \(A\). 5. **Analyzing the Relationship**: From the rearranged equation, we can conclude that: - If the cross-sectional area \(A\) increases, the force \(F\) required to produce the same elongation \(l\) decreases. - If the length \(L\) increases, the force \(F\) required to produce the same elongation \(l\) also decreases. 6. **Conclusion**: The correct statement is that the elongation \(l\) is inversely proportional to the cross-sectional area \(A\) of the bar, given a constant force \(F\) and Young's modulus \(Y\).

To solve the problem, we need to analyze the relationship between the force applied to the iron bar, its elongation, cross-sectional area, and Young's modulus. ### Step-by-Step Solution: 1. **Understanding Young's Modulus**: Young's modulus (Y) is defined as the ratio of longitudinal stress to longitudinal strain. Mathematically, it can be expressed as: \[ Y = \frac{\text{Stress}}{\text{Strain}} ...
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