Home
Class 12
PHYSICS
A wire is stretched under a force. If th...

A wire is stretched under a force. If the wire suddenly snaps, the temperature of the wire

A

remains the same

B

decreases

C

increases

D

first decreases then increases

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of what happens to the temperature of a wire when it is stretched under a force and then suddenly snaps, we can follow these steps: ### Step 1: Understand the Concept of Work Done When a wire is stretched, work is done on the wire. This work is related to the force applied and the elongation of the wire. The formula for work done (W) can be expressed as: \[ W = F \cdot d \] where \( F \) is the force applied and \( d \) is the elongation of the wire. **Hint:** Remember that work done on an object can lead to changes in energy. ### Step 2: Energy Storage in the Wire The work done on the wire is stored as potential energy in the form of elastic potential energy. When the wire is stretched, this energy is stored in the material of the wire. **Hint:** Think about how energy can be stored in materials when they are deformed. ### Step 3: Conversion of Energy to Heat When the wire suddenly snaps, the stored elastic potential energy is released. This energy does not just disappear; it is converted into heat energy. The conversion of this energy results in an increase in the temperature of the wire. **Hint:** Consider how energy transformations occur in physical processes, especially when materials undergo sudden changes. ### Step 4: Conclusion Since the work done on the wire is converted into heat energy upon snapping, we can conclude that the temperature of the wire increases when it suddenly snaps. **Final Answer:** The temperature of the wire increases when it suddenly snaps.

To solve the problem of what happens to the temperature of a wire when it is stretched under a force and then suddenly snaps, we can follow these steps: ### Step 1: Understand the Concept of Work Done When a wire is stretched, work is done on the wire. This work is related to the force applied and the elongation of the wire. The formula for work done (W) can be expressed as: \[ W = F \cdot d \] where \( F \) is the force applied and \( d \) is the elongation of the wire. **Hint:** Remember that work done on an object can lead to changes in energy. ...
Promotional Banner

Topper's Solved these Questions

  • BULK PROPERTIES OF MATTER

    MTG-WBJEE|Exercise WB JEE WORKOUT (ONE OR MORE THAN ONE OPTION CORRECT TYPE )|10 Videos
  • BULK PROPERTIES OF MATTER

    MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS (SINGLE OPTION CORRECT TYPE)|22 Videos
  • ATOMS MOLECULES AND CHEMICAL ARITHEMETIC

    MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS CATEGORY 1: SINGLE OPTION CORRECT TYPE (1 MARK)|3 Videos
  • CURRENT ELECTRICITY

    MTG-WBJEE|Exercise WB JEE PREVIOUS YEARS QUESTIONS|21 Videos

Similar Questions

Explore conceptually related problems

A weight is suspended from a long metal wire. If the wire suddenly breaks, its temperature

A wire having Young's modulus 2 xx 10^(11)N//m^(2) is stretched by a force. If the energy stored per unit volume of the wire is 40 "joule"//m^(3) , then the stress produced in the wire is

If a wire is stretched to its length, then

If a wire is stretched to four times its length, then the specific resistance of the wire will

A copper wire 2m long is stretched by 1mm . If the energy strored in the stretched wire is converted into heat, then calculate the rise in temperature of the wire.

A wire stretches a certain amount under a load. If the load and the diameter both increased to three times, then the stretch produced in the wire

One metre long sonometer wire is stretched with a force of 4kg wt, another wire of same material and diamter is arranged along a side. The second wire is stretched with a force of 16kg wt. if the length of the second wire is in its second harmonic is the same as fifth harmonic of the first wire, then the length of the second wire will be

A wire of length 1m is stretched by a force of 10N. The area of cross-section of the wire is 2 × 10^(–6) m^(2) and Y is 2 xx 10^(11) N//m^(2) . Increase in length of the wire will be -

When a wire is stretched by a force the strain produced in the wire is 2 xx 10^(-4) . If the energy stored per unit volume of the wire is 4 xx 10^(4) "joule"//m^(3) then the Young's modulus of the material of the wire will be,