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A liquid flows through two capillary tub...

A liquid flows through two capillary tubes A and B connected in series. The length and radius of B are twice that of A. What is the ratio of the pressure difference across A to that across B ?

A

`1:16`

B

`8:1`

C

`1:8`

D

`1:2`

Text Solution

Verified by Experts

The correct Answer is:
B
According to poiseuille formula , the rate of flow of liquid through capillary tube is
`Q = (pi P r^4)/(8 eta l)`
therfore `Q_A = Q_B`
`(pi P_A r_A^4)/(8 eta l_A) = (pi P_B r_B)/(8 eta l_B)`
` therefore P_A/P_B= (r_B/r_A)^4 (l_A/l_B) = ( (2r_A)/(2l_A))^4 ( (l_A)/(2l_A)) = 16 xx 1/2 = 8:1`
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