In simple harmonic motion,the particle is

The equation of simple harmonic motion of two particle is x_1=A_1" "sin" "omegat and x_2=A_2" "sin(omegat+prop) . If they superimpose, then the amplitude of the resultant S.H.M. will be

A simple harmonic motion of a particle is represented by an equation x= 0.01 sin [100 pi (t +0.05)] . Where x is metre and t is in second respectively. The value of time period is…………

A simple harmonic motion of a particle is represented by an equation x= 5 sin(4t -(pi)/(6)) , where x is its displacement. If its displacement is 3 unit then find its velocity.

The equation of a simple harmonic motion of a particle is (d^(2)x)/(dt^(2)) + 0.2 (dx)/(dt) + 36x = 0 . Its time period is approximately

The equation of simple harmonic motion of two particle is x_1=A_1" "sin" "omegat and x_2=A_2" "sin(omegat+prop) . If they superimpose, then the amplitude of the resultant S.H.M. will be

In simple harmonic motion of a particle, maximum kinetic energy is 40 J and maximum potential energy is 60 J. then

In simple harmonic motion of a particle, maximum kinetic energy is 40 J and maximum potential energy is 60 J. then

The simple harmonic motion of a particle is given by x = a sin 2 pit . Then, the location of the particle from its mean position at a time 1//8^(th) of second is