If `A=(1,-2,-1) , B=(4,0,-3),C= (1,2,-1),D=(2,-4,-5) ` then find distance between `bar(AB),bar(CD)`

If A=(1, -2, -1), B= (4, 0, -3), C = (1, 2, -1), D=(2, -4, -5) , then distance between AB and CD is

A : If A = (1, -2, -1) B = (4, 0, - 3), C = (1,2 - 1), d = (2, -4,-5) then the distance between AB and CD is 4/3 R : The shortest distance between the skew lines r = a + sb, r = c + td is ([a - c b d])/(|b xx d|)

If A-=(3,4-2),B-=(1,-1,2),C-=(0,3,2) and D-=(3,5,6) , then the angle between bar(AB) and bar(CD) is

If A (4, 3, 5), B (6, 4, 3), C (2, -1, 4), D (0, 1, 5) then the projection of bar(AB) " on " bar(CD) is

Vertices of a parallelogram taken in order are A, ( 2,-1,4) , B (1,0,-1) , C ( 1,2,3) and D (x,y,z) The distance between the parallel lines AB and CD is

Vertices of a parallelogram taken in order are A, ( 2,-1,4) , B (1,0,-1) , C ( 1,2,3) and D (x,y,z) The distance between the parallel lines AB and CD is