The heat capacity of a metal is 4200 J/k. Its water equivalent is -

The thermal capacity of a body is 80 cal , then its water equivalent is

A calorimeter of mass 60 g contains 180 g of water at 29^(@)C . Find the final temperature of the mixture, when 37.2 g of ice at - 10^(@)C is added to it (specific heat capacity of water = 4200 J//kg K. latent heat of ice 336 xx 10^(3)J//kg . Specific heat capacity of ice = 2100 J//kg K , specific heat capacity of the calorimeter is 0.42 Jg^(-1) xx C^(-1) )

Thrmal capacity of a body and its water equivalent are _______ equal.

Calorimetry: Temperature| Heat | Specific heat capacity | Heat capacity| Water equivalent | Principle of calorimetry

Calculate the amount of heat given out while 400 g of water at 30^@C is cooled and converted into ice at -2^@C . Specific heat capacity of water = 4200 J/kg K Specific heat capacity of ice = 2100 J/ kg K Specific latent heat of fusion of ice = 33600 J/kg

Some heat energy is given to 120 g of water and its temperature rises by 10 K. When the same amount of heat energy is given to 60 g of oil, its temperature rises by 40 K. The specific heat capacity of water is 4200 J kg- K^(-1) . Calculate : (i) the amount of heat energy in joule given to water, and (ii) the specific heat capacity of oil.

Calorimetry: Temperature, Heat, Specific heat capacity | Heat capacity | Water equivalent | Principle of calorimetry | Latent heat | Heating curve (phase change)

The specific heat capacity of a metal is 160 "J Kg"^(-1)K^(-1) . Calculate the amount of heat energy required to raise the temperature of 500 gram of the metal from 125^@ C" to " 325^@ C.

Calculate heat capacity of 20 kg of water, given that sp. heat capacity of water- 4.2 J//g^(@)C .