At `25^(@)C`, the bond dissociation energy of `N_(2)(g)` is 946 `kJ*mol^(-1)`. What does it mean ? What would be the standard atomisation enthalpy of `N_(2)(g)` at `25^(@)C` ?

"At 25^(@)C , the standard heat of formation of H_(2)O(l) is -285.83kJ*mol^(-1) "-What does it mean?

At 25^(@)C the standard heat of formation of liquid benzene is +49.0 kJ*mol^(-1) -what does it mean?

What do you mean by the standard enthalpy of atomisation of chlorine at 25^(@)C=+121kJ*mol^(-1) ?

The standard bond dissociation energy of A_(2)(g),B_(2)(g) and AB(g) molecules are x, y and z kJ*mol^(-1) respectively. What will be the standard enthalpy of formation of AB(g)?

At 25^(@)C and 1 atm if the bond energy of Cl_(2)(g) is 242kJ*mol^(-1) , then the standard enthalpy of atomisation of chlorine at the same temperature+_____.

If the bond energy of C-H bond is +416.18 kJ*mol^(-1) , then what will be the enthalpy of formation of C-H bond?

A-B bonds present in AB_(3)(g) molecule undergo stewise dissociation by the following sequence of steps. (i) AB_(3)(g)toAB_(2)(g)+B(g) (ii) AB_(2)(g) to AB(g)+B(g) (iii) AB(g)toA(g)+B(g) At 25^(@)C , if the enthalpy changes in steps (i) and (iii) are x and z kJ*mol^(-1) , respectively, and the bond dissociation energy of A-B bond is y kJ*mol^(-1) , then what would be the enthalpy change in step (ii)?

At 25^(@)C , the standard reaction enthalpy for the reaction, 2C(graphite, s) +O_(2)(g)to2CO(g) is -221.0kJ. Does this enthalpy change indicate the standard enthalpy of formation of CO(g) ? If not, then what would be the value of the enthalpy of formation of CO(g) at 25^(@)C ?

Bond dissociation enthalpies of H_(2(g)) and N_(2(g)) are "426.0 kJ mol"^(-1) and "941.8 kJ mol"^(-1) , respectively, and enthalpy of formation of NH_(3(g))" is "-"46 kJ mol"^(-1) . What are the enthalpy of atomisation of NH_(3(g)) and the average bond enthalpy of N-H bond respectively ( in kJ "mol"^(-1) )?