[pH" of "0.1MNa_(2)HPO_(4)" and "0.2MNaH_(2)PO_(4)" respectively are ":(pK_(a)" for "H_(3)PO_(4)" are "2.2,7.2" and "12.0" )."],[[" (A) "4.7,9.6," (B) "9.6,4.7," (C) "4.7,5.6," (D) "5.6,4.7]]

pH of 0.1 M Na_2HPO_4 and 0.2 M NaH_2PO_4 are respectively : ( pK_a for H_3PO_4 are 2.2,7.2,12.0)

pH of 0.1M Na_(2)HPO_(4) and 0.2M NaH_(2)PO_(4) are respectively: (pK_(a)"for" H_(3)PO_(4) are 2.12, 7.21 and 12.0 for respective dissociation to H_2PO_(4)^(-), HPO_(4)^(2-) and PO_(4)^(3-)) :

pH of 0.1M Na_(2)HPO_(4) and 0.2M NaH_(2)PO_(4) are respectively: (pK_(a)"for" H_(3)PO_(4) are 2.12, 7.21 and 12.0 for respective dissociation to HPO_(4)^(2-), HPO_(4)^(-) and PO_(4)^(3-)) :

Calculate pH a) NaH_(2)PO_(4) b) Na_(2)HPO_(4) respectively, for H_(3)PO_(4) pKa_(1) = 2.25, pKa_(2) = 7.20, pKa_(3) = 12.37 )

The addition of NaH_(2)PO_(4) to 0.1M H_(3)PO_(4) will cuase

The addition of NaH_(2)PO_(4) to 0.1M H_(3)PO_(4) will cuase

pK_(a1) , pK_(a_(2)) and pK_(a_(3)) of H_(3)PO_(4) are respectively x,y and z. pH of 0.1 M Na_(2)HPO_(4) solution is

What is the n-factor for H_(2)PO_(4) in the reaction 2NaOH+H_(3)PO_(4)rarr Na_(2)HPO_(4)+2H_(2)O ?

What will be the pH of a solution formed by mixing 10 ml 0.1 M NaH_(2)PO_(4) and 15 mL 0.1 M Na_(2)HPO_(4) ? ["Given: for "H_(3)PO_(4)Pk_(a_(1))=2.12, Pk_(a_(2))=7.2]