Arithmetic mean = (sum of all observations)/(Number of observations)

"(Sum of observations)"/"(Number of observations)" = ....

The arithmetic mean of 10 observations is 45. If one of the obsservations, 54, is deleted, then find the mean of the remaining observations.

The arithmetic mean of 13 observations is 60. If one of the observation 50 is deleted and another observation 63 is included. Find the new arithmetic mean. The following steps are involved in solving the above problem. Arrange them in sequential order. (A) New sum of observations =780-50+63=793 (B) The sum of the observation =13xx60=780 (C) :. New arithmetic mean =793/13 (D) The required mean =61

The value of arithmetic mean of differences of a finite number of observations from their arithmetic mean is……….

The arithmetic mean of 12 observations is 15. If two observations 20 and 25 are removed then the arithmetic mean of remaining observations is

The sum of the all the observations divided by number of observation is___.

The mean of 36 observations is 22.If one observation 22 is deleted ,then find the new mean The following steps are involved in solving the above problem .Arrange then in sequential order . therefore New arithmetic mean =770/35 = 22 ( B) Arithemetic mean ="The sum of the observations "/"Total number of the observations" rArr 22 ="The sum of the observations "/36 ( C) The sum of the observations 22 is deleted , the new sum = 792 -22 = 770 and the number of observations is 36 -1 ,i.e 35,.