Simplify : `(1)/(1+x^(m-n)+x^(m-p))+(1)/(1+x^(n-p)+x^(n-m))+(1)/(1+x^(p-m)+x^(p-n))`.

Simplify the following: 1/(1+x^(m-n)+x^(m-p))+(1)/(1+x^(n-p)+x^(n-m))+(1)/(1+x^(n-m)+x^(p-n))

If y=(1)/(1+x^(n-m)+x^(p-m))+(1)/(1+x^(m-n)+x^(p-m))+(1)/(1+x^(m-p)+x^(n-p)) the (dy)/(dx) is

Simplify (i) ((x^(i))/(x^(m)))^((1)/(lm)).((x^(m))/(x^(n)))^((1)/(m)).((x^(n))/(x^(l)))^((1)/(nl)) (ii) ((x^(p))/(x^(q)))^((1)/(ml)).((x^(q))/(x^(r)))^((1)/(mn)).((x^(r))/(x^(p)))^(r+q)

Solve 1/(1+p^(m-n))+1/(1+p^(n-m))

If y=1/(1+x^(n-m)+x^(p-m))+1/(1+x^(m-n)+x^(p-n))+1/(1+x^(m-p)+x^(n-p)) then (dy)/(dx) at e^m^n^p is equal to: e^(m n p) (b) e^(m n//p) (c) e^(n p//m) (d) none

Simplify : ((p+(1)/(q))^m(p-(1)/(q))^n)/((q+(1)/(p))^m(q-(1)/(p))^n) .

If y=1/(1+x^(n-m)+x^(p-m))+1/(1+x^(m-n)+x^(p-n))+1/(1+x^(m-p)+x^(n-p)) , then (dy)/(dx) is equal to

Differential coefficient of (x^((l + m)/(m - n)))^(1/(n-1)).(x^((m +n)/(n -1)))^(1/(l - m)).(x^((n + 1)/(l - m)))^(1/(m -n)) w.r.t x is

{(P+1/(q))^(m).(p-(1)/(q))^(n)}/{(q+(1)/(p))^(m).(q-(1)/(p))^(n)}