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In double-slit Experiment using light of...

In double-slit Experiment using light of wavelength 600 nm, the angular width of a fringe formed on a distance screen is `0.1^(@)`. What is the spacing between the two slits?

Text Solution

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Here wavelength of light `l=600nm=6xx10^(-7)m` and angular width of fringe a`=0.1^(@)`
As angular width `alpha=(lamda)/(d)`, hence spacing between the two slits `d=(lamda)/(alpha)`
`therefore d=(6xx10^(-7)m)/((0.1xx(pi)/(180))rad)=3.43xx10^(-4)mcong3.4xx10^(-4)m`.
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In double slit experiment using light of wavelength 600 nm , the angular width of a fringe formed on a distant screen is 0.1^(@) . What is the spacing between the two slits ?

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Knowledge Check

  • In Young's double slit experiment, the angular width of a fringe formed on a distant screen is 0.1^(@) . What is the spacing between the slits, if the waveelngth of light used is 6000 Å?

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