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Laser light of wavelength 630 nm inciden...

Laser light of wavelength 630 nm incident on a pair of slits produces an interference pattern in which the bright fringes are separated by 8.1 mm. a second light produces an interference pattern in which the fringes are separated by 7.2 mm. calculated the wavelength of the second light.

Text Solution

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From relation `beta=(lamdaD)/(d)`, we find that, other factors remaining unchanged `(beta.)/(beta)=(lamda.)/(lamda)`
In present problem `beta=8.1`mm, `beta.=7.2mm and lamda=630mm`
`therefore lamda.=(beta.)/(beta)*lamda=(7.2mm)/(8.1mm)xx630nm=560nm`
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Laser light of wavelength 630 mm incident on a pair of slits produces as interference pattern in which the bright fringes are separated by 8.1 mm. A second light produces an interference pattern in which the fringes are separated by 7.2 mm. Calculate the wavelength of the second light.

Laser light of wavelength 640 nm incident on a pair of slits produces an interference patterns in which the bright fringes are separated by 8.1 mm. A second light produces an interference pattern in which the fringes and separated by 7.2 mm. Calculate the wavelength of the second light.

Knowledge Check

  • In the interference pattern all the fringes are of equal emit light of

    A
    intensity
    B
    contrast
    C
    width
    D
    all of these

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