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A proton and an electron have same kinet...

A proton and an electron have same kinetic energy. Which one has greater de-Broglie wavelength and why?

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As `lamda=(h)/(sqrt((2mK)))` and kinetic energy K is constant, hence `lamdaprop(1)/(sqrtm)` i.e., electron particle, being lighter, will have the larger de-Broglie wavelength. Thus `lamda_(e) gt lamda_(p)`.
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Knowledge Check

  • If a proton and an electron have the same kinetic energy, which has the longer de Broglie wavelength?

    A
    Electron
    B
    Proton
    C
    Both have the same wavelength
    D
    None of the above

  • An electron and a proton have same kinetic energy Ratio of their respective de-Broglie wavelength is about

    A
    `(12.27)/(0.266)`
    B
    `(0.101)/(0.266) `
    C
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    D
    `(0.101)/(12.27)`

  • An electron is having a kinetic energy of 50 eV. Its de-Broglie wavelength is

    A
    `1.737 Å`
    B
    `2.5 Å`
    C
    `4.414 Å`
    D
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