An electron is accelerated through a potential difference of 100 volts. What is the de-Broglie wavelength associated with it ? To which part of the electromagnetic spectrum does this value of wavelength correspond ?

Explanation

The accelerating voltage `V=100V`
`therefore`de-Broglie wavelength of electron `lamda=(h)/(sqrt(2emV))=(6.626xx10^(-34))/(sqrt(2xx1.602xx10^(-19)xx9.1xx10^(-31)xx100))`
`=1.227xx10^(-10)m or 1.227Å`
The value of de-Broglie wavelength corresponds to X-rays part of electromagnetic spectrum.