An electron and a proton are moving in the same direction and possess same kinetic energy. Find the ratio of de-Broglie wavelengths associated with these particles.

Explanation

We know that de-Broglie wavelength `lamda=(h)/(mv)=(h)/(sqrt(2mK))`, where K is the kinetic energy. As `m_(p)gtm_(e)`, hence it is clear that for same kinetic energy.
`(lamda_(e))/(lamda_(p))=sqrt((m_(p))/(m_(e)))`.
`implies lamda_(e) lamda_(p)` i.e, de-Broglie wavelength of electron will be greater than that of proton.