Sketch the graphs showing variation of stopping potential with frequency of incident radiations for two photosensitive materials A and B having threshold frequencies `v_(A) gt v_(B)`.
(i) In which case is the stopping materials A and B having threshold frequencies `v_(A) gt V_(B)`.
(i) In which case is the stopping potential more and why?
(ii) Does the slope of the graph depend on the nature of the materials used ? Explain.

Explanation

The graphs showing variation of stopping potential `V_(0)` with frequency v of incident radiation for two photosensitive materials A and B, having threshold frequencies `v_(A) and v_(B)(v_(A)gtv_(B))` are shown in here. the graphs are straight line graphs.
(i) The stopping potential `V_(0)=(h)/(e)(v-v_(0))`, where `v_(0)` is the threshold frequency. As threshold frequency of A is more than that for B, it is obvious that for an incident radiation of given frequency the stopping potential for B is more than for A.
(ii) The slope of the graph is `h/e`, which is independent of the nature of the photosensitive material used.