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Calculate the maximum kinetic energy of electrons emitted from a photosensitive surface of work function 3.2 eV, for the incident radiation of wavelength 300 nm.

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The correct Answer is:
`0.94eV`
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The kinetic energy of photoelectrons emitted by a photosensitive surface depends on the internsity of the incident radiation

(a) Photoelectric threshold of metallic silver is lambda =3800 Å . Ultravilolet light of lambda =260 nm is incident on silver surface. Calculate : (i) the value of work function in joule and eV K_(max) of the emitted photoelectrons (iii) v_(max) of the photoelectrons (b) Ultraviolet light of wavelength 280 nm is used in an experiment on photoelectric effict with lithium (phi =2.5 eV) cathode. Find (i) the maximum kinetic energy of the photoelectrons (ii) the stopping potential (c) Find the maximum magnitude of the linear momentum of a photelectron emitted when light of wavelength 400 nm falls on a metal (phi =2.5 eV) . (d) A monochromitc light source of intensity 5 mW emits 8xx10^(5) photons per second. This light ejects photoelectrons from a metal surface. The stopping potential for this set up is 2.0 V . Calculate the work function of the metal. (e) The maximum kinetic energy of photoelectrons emitted from a certain metallic surface is 30 eV when imonochromatic radiation of wavelength lambda falls on it. When the same surface is illuminated with light of wavelength 2 lambda the maximum kinetic energy of photo electrons is observed to be 10 eV. Calculate the wavelength lambda and determine the maximum wavelength of incident radiation for which photoelectrons can be emitted by this surface.

Knowledge Check

  • If light of wavelength of maximum intensity emitted from surface at temperature T_(1) Is used to cause photoelectric emission from a metallic surface, the maximum kinetic energy of the amitted electron is 6 ev, which is 3 time the work function of the metallic surface. If light of wavelength of maximum intensity emitted from a surface at temperature T_(2) (T_(2)=2T_(1)) is used, the maximum kinetic energy of the photoelectrons emitted is

    A
    2 eV
    B
    4 eV
    C
    14 eV
    D
    18 eV

  • The kinetic energy of most energetic electrons emitted from a metallic surface is doubled when the wavelength lamda of the incident radiation is changed from 400 nm to 310 nm. The work function of the metal is

    A
    0.9 eV
    B
    1.7 eV
    C
    2.2 eV
    D
    3.1 eV

  • If light of wavelength 6200Å falls on a photosensitive surface of work function 2 eV, the kinetic energy of the most energetic photoelectron will be

    A
    0.5 eV
    B
    1 eV
    C
    zero
    D
    0.75 eV

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    The maximum kinetic energy of photoelectrons emitted from a metal surface increses from 0.4 eV to 1.2 eV when the frequency of the incident radiation is increased by 40% . What is the work function (in eV) of the metal surface?

    Find the maximum kinetic energy of electrons ejected from a certain material if the material's work function is 2.3 eV and the frequency of the incident radiation is 2.5 xx 10^(15) Hz .

    The maximum kinetic energy of photoelectrons emitted from a metalic surface is 30 eV when monochromatic radiation of wavelength falls on it. When the same surface is illuminated with light of wavelength 2lambda the maximum kinetic energy photo electrons is observed to be 10 eV Calculate the wavelength lambda and determine the maximum wavelength of incident radiation for which photoelectrons can be emitted by this surface, (h = 6.62 xx 10^(-34) JS =4.14 xx 10^(-15) eV-s. c = 3 xx 10^(8) m//s)

    The kinetic energy of.most energetic electrons emitted from a metallic surface is doubled when the wavelength of the incident radiation is changed from 400 nm to 310 nm . The work function (in eV ) of the metal is

    Maximum kinetic energy of photoelectrons emitted from a metal surface, when light of wavelength lambda is incident on it, is 1 eV. When a light of wavelength lambda/3 is incident on the surfaces, maximum kinetic energy becomes 4 times. The work function of the metal is

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