A second's pendulum is taken to a height where the value of g is `4.36ms^(-2)`. What will be its new time period?

A seconds' pendulum is taken to a place where acceleration due to gravity falls to one-fourth. How is the time period of the pendulum affected, if at all ? Give reason. What will be its new time period ?

A simple pendulum designed on the moon as a seconds pendulum is taken to a planet where the acceleration due to gravity on the surface is twice that on the Earth . If g_("earth") : g_("moon") =6 :1 find the period of oscillation of the pendulum on the planet mentionedabove.

A second's pendulum is taken from a place where g=9.8 ms^(-2) to a place where g=9.7 ms^(-2) .How would its length be changed in order that its time period remains unaffected ?

The mass and radius of a satellite is twice that of the earth. If a seconds pendulum is taken to that satellite, what will be its time period?

A second pendulum is arranged in a lift . If th elift is moving up with an acceleration g//4 . Its new time period will be