AC is diameter of circle. AB is a tangent.BC meets the circle again at D. `AC = 1 , AB = a, CD-b`, then :

AB is a diameter of a circle. BP is a tangent to the circle at B . A straight line passing through A intersects BP at C and the circle at D . Prove that BC^(2)=ACxxCD .

If AOB is a diameter of a circle and C is a point on the circle, then AC^(2)+BC^(2)=AB^(2) .

If AOB is a diameter of a circle and C is a point on the circle, then AC^(2)+BC^(2)=AB^(2) .

In the given figure, AB is the diameter of the circle centered at O. If angle COA = 60^(@) , AB = 2r , AC = d . and CD = l, then l is equal to

In the given figure, AB is the diameter of the circle, centered at O. If angleCOA = 60^(@), AB = 2r, AC = d, and CD = l , then l is equal to

The tangent drawn from an extenral point A of the circle with centre C touches the circle at B. If BC =5 cm, AC=13 cm, then the length of AB=

The circle above with centre A has an area of 21. BC is tangent to the circle with centre A at point B. IF AC=2AB, then what is the area of the shaded region?