The straight line 2x-3y = 1 divides the circular region `x^2+ y^2 le6` into two parts. If S = { `( 2 , 3/4) , (5/2,3/4) , (1/4,-1/4), (1/8,1/4)`}, then the number of point(s) in S lying inside the smaller part is

The straight line 2x - 3y = 1 divides the circular region x^2+y^2le6 into two parts. If S = {(2,3/4),(5/2,3/4),(1/4,-1/4),(1/8,1/4)} , then the number of point(s) in S lying inside the smaller part is

The straight line 2x-3y=1 divides the circular region x^(2)+y^(2)<=6 into two parts.If S={(2,(3)/(4)),((5)/(2),(3)/(4)),((1)/(4),-(1)/(4)),((1)/(8),(1)/(4))} then the number of point(s) in s lying inside the smaller part is

The straight line 2x – 3y = 1 divides the circular region x^(2) + y^(2) le 6 into two parts. If S = {(2, (3)/(4)), ((5)/(2), (3)/(4)), ((1)/(4), -(1)/(4)), ((1)/(8), (1)/(4))} , then the number of point(s) in S lying inside the smaller part is

Let the straight line x=b divide the area enclosed by y=(1-x)^2, y=0 and x=0 into two parts R_1 (0 le x le b) and R_2(b le x le 1) such that R_1-R_2=1/4 .Then b equals :

Let the straight line x = b divide the area enclosed by y = (1-x)^(2), y = 0 and x = 0 into two parts R_(1) (0 le x le b) and R_(2) (b le x le 1) such that R_(1) - R_(2) = 1/4 . Then b equals

The parabolas y^(2)= 4x and x^(2) = 4y divide the square region bounded by the line x = 4 , y = 4 and the coordinate axes into three parts. If S_(1), S_(2), S_(3) are respectively the areas of these three parts numbered from top to bottom then S_(1) : S_(2) : S_(3) is-

Let the straight line x=b divide the area enclosed by y=(1-x)^2, y=0 and x=0 into two parts R_1 (0 le x le b) and R_2 (b le x le 1) such that R_1-R_2=1/4 . Then b equals (A) 3/4 (B) 1/2 (C) 1/3 (D) 1/4

If the straight line x=b divide the area enclosed by y=(1-x)^(2),y=0 " and " x=0 " into two parts " R_(1)(0le x le b) " and " R_(2)(b le x le 1) " such that " R_(1)-R_(2)=(1)/(4). Then, b equals