[4" The equation of the circle passing through the origin is "],[x^(2)+y^(2)-6x+2y=0." What is the equation of its any one "],[" diameter? "]

Equation of a circle passing through origin is x^(2) + y^(2) - 6x + 2 y = 0 . What is the equation of one of its diameter ?

The equation of diameter of a circle passing through origin is x+y=1 and the greatest distance of any point of the circle from the diameter is sqrt(5) , then an equation of the circle is: (A) x^2+y^2-2x+4y=0 (B) x^2+y^2-4x+2y=0 (C) x^2+y^2+2x-2y=0 (D) none of these

Find the equation of the circle passing through (-2,14) and concentric with the circle x^(2)+y^(2)-6x-4y-12=0

Find the equation of the circle passing through (-2,14) and concentric with the circle x^(2)+y^(2)-6x-4y-12=0

Find the equation of the circle passing through (-2,14) and concentric with the circle x^(2)+y^(2)-6x-4y-12=0